Question

PLEASE HELP!!
Look at the square ABCD below. A(- 2, 0) B(0, 6) C(6,4) and D(4, - 2)




What is its perimeter?

8sqrt(40)

8sqrt(10)

4sqrt(80)

4sqrt(10)

Answer 1

Where is the square

Answer 2

please send a pic of it

Answer 3

ok i will look at it

Answer 4

Thank you :)

Answer 5

what grade are you in

Answer 6

Sophomore

Answer 7

oh that is why I don't remember learning this I can try to help but I might be wrong

Answer 8

Ok your fine I learned some of this last year but I don’t really remember any of it

Answer 9

To find the perimeter of the square, we need to find the distance between its four sides, which are the line segments connecting points A to B, B to C, C to D, and D to A.

Using the distance formula:

distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

We can find the distance between points A and B as:

AB = sqrt((0 - (-2))^2 + (6 - 0)^2)
AB = sqrt(4^2 + 6^2)
AB = sqrt(52)
AB = 2sqrt(13)

Similarly, we can find the distance between points B and C as:

BC = sqrt((6 - 0)^2 + (4 - 6)^2)
BC = sqrt(6^2 + 2^2)
BC = 2sqrt(10)

We can find the distance between points C and D as:

CD = sqrt((4 - 6)^2 + (-2 - 4)^2)
CD = sqrt((-2)^2 + (-6)^2)
CD = 2sqrt(10)

Finally, we can find the distance between points D and A as:

DA = sqrt((-2 - (-2))^2 + (-2 - 0)^2)
DA = sqrt(0^2 + (-2)^2)
DA = 2

Therefore, the perimeter of the square is:

AB + BC + CD + DA = 2sqrt(13) + 2sqrt(10) + 2sqrt(10) + 2
Perimeter = 2sqrt(13) + 4sqrt(10) + 2

I hope this helps!