Determine the power set for T = {elm, pine, oak}. P(T) = {{elm}, {pine}, {oak}, {elm, pine}, {elm, oak}, {pine, oak}} P(T) = {{elm}, {pine}, {oak}, {elm, pine, oak}} P(T) = {{ }, {elm}, {pine}, {oak}, {elm, pine}, {elm, oak}, {pine, oak}, {elm, pine, oak}, {elm, pine, oak, palm}} P(T) = {{ }, {elm}, {pine}, {oak}, {elm, pine}, {elm, oak}, {pine, oak}, {elm, pine, oak}}
The power set for T = {elm, pine, oak} is: c. P(T) = {{ }, {elm}, {pine}, {oak}, {elm, pine}, {elm, oak}, {pine, oak}, {elm, pine, oak}, {elm, pine, oak, palm}} This is because the power set of a set is the set of all possible subsets of that set, including the empty set and the set itself. In this case, T has 3 elements, so there are 2^3 = 8 possible subsets. These are: - The empty set {} - The singleton sets {elm}, {pine}, and {oak} - The doubleton sets {elm, pine}, {elm, oak}, and {pine, oak} - The set T itself {elm, pine, oak} Option c lists all of these subsets, including the empty set and the set T.
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