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KarmaXD · Answer

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KarmaXD · Answer

i'm always getting stuck on algebra

KarmaXD · Answer

@toga

toga · Answer

Using the Pythagorean Theorem, we know that a² + b² = c², where c is the hypotenuse.

In this case, we are given the lengths of the two legs of the right triangle: a = 12 and b = 16. So, we can plug those values into the equation:

12² + 16² = c²

144 + 256 = c²

400 = c²

To solve for c, we can take the square root of both sides:

√400 = √c²

20 = c

Therefore, the length of the hypotenuse is 20 units.

KarmaXD · Answer

@toga wrote:

Using the Pythagorean Theorem, we know that a² + b² = c², where c is the hypotenuse. In this case, we are given the lengths of the two legs of the right triangle: a = 12 and b = 16. So, we can plug those values into the equation: 12² + 16² = c² 144 + 256 = c² 400 = c² To solve for c, we can take the square root of both sides: √400 = √c² 20 = c Therefore, the length of the hypotenuse is 20 units.

thank you!

toga · Answer

@karmaxd wrote:

@toga wrote:

Using the Pythagorean Theorem, we know that a² + b² = c², where c is the hypotenuse. In this case, we are given the lengths of the two legs of the right triangle: a = 12 and b = 16. So, we can plug those values into the equation: 12² + 16² = c² 144 + 256 = c² 400 = c² To solve for c, we can take the square root of both sides: √400 = √c² 20 = c Therefore, the length of the hypotenuse is 20 units.

thank you!

np

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