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Chemistry 12 Online
jjisdrained:

my stoichiometry I need hep with a decomposition soichieomitry ex: Iron (III) oxide (Fe₂O₃) reacts with carbon monoxide (CO) to produce iron (Fe) and carbon dioxide (CO₂). If you start with 160 grams of iron (III) oxide, determine the following:

Karina2222:

To find the mass of iron that can be obtained from the reaction, we can use stoichiometry to calculate the amount of iron (Fe) produced from the given amount of iron (III) oxide (Fe2O3). First, we need to write the balanced chemical equation for the reaction between iron (III) oxide and carbon monoxide: Fe2O3 + 3CO → 2Fe + 3CO2 From the balanced equation, we can see that 1 mole of Fe2O3 produces 2 moles of Fe. Next, we calculate the moles of Fe2O3: moles of Fe2O3 = mass of Fe2O3 / molar mass of Fe2O3 moles of Fe2O3 = 3.80 g / 159.69 g/mol = 0.0238 moles Using the stoichiometry of the reaction, we can determine the moles of Fe produced: moles of Fe = moles of Fe2O3 × (2 moles of Fe / 1 mole of Fe2O3) moles of Fe = 0.0238 moles × 2 = 0.0476 moles Finally, we can calculate the mass of Fe produced: mass of Fe = moles of Fe × molar mass of Fe mass of Fe = 0.0476 moles × 55.85 g/mol = 2.66 g Therefore, the mass of iron (Fe) that can be obtained from 3.80 g of iron (III) oxide (Fe2O3) reacting with excess carbon monoxide (CO) is 2.66 g.

poopoopeepee:

lmao the speed at which that answer was generated indicates it was copy pasted.

Karina2222:

true but at least it's an answer i don't see you giving one

poopoopeepee:

well hard to answer a question when it's not completed yet.

Karina2222:

okok whatevs

jjisdrained:

ty tysm for ur help < 333

poopoopeepee:

anyways if that answer's off chegg it's probably right, if you want to get what's going on just ask specific questions and i can explain

Karina2222:

your welcome, and sorry

Treeko:

@poopoopeepee wrote:
anyways if that answer's off chegg it's probably right, if you want to get what's going on just ask specific questions and i can explain
LMAO FR FR

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