Ask your own question, for FREE!
Mathematics 9 Online
Coyote:

Trigonometry

Coyote:

1 attachment
Coyote:

@extrinix

ThisGirlPretty:

@dude @shadow

Coyote:

Oop tagged the senior mods…

Extrinix:

You must use the \(SOH~CAH~TOA\) rule in order to solve this. For the lower balloon, your side value is on the Hypotenuse compared to the angle. Meaning you must use \(cos\) in order to figure out what the length of the \(adjacent\) side is. The adjacent side is the side that you're using to figure out the difference between the height of the balloons. \(Cos~(\theta)~=~\dfrac{Adjacent}{Hypotenuse}\) Now, your adjacent is undefined, and your hypotenuse is defined (515m). \(Cos~(15)~=~\dfrac{x}{515}\) If you put that into your calculator, you will have the \(adjacent\) side for the lower balloon.

Extrinix:

Now, in order to get the actual distance between each balloon, you need to find the \(adjacent\) side of the other balloon. Since we're looking for the adjacent side, and the Hypotenuse is defined, we will be using \(cos\) once again. \(Cos~(\theta)~=~\dfrac{Adjacent}{Hypotenuse}\) Our value for the hypotenuse is \(840m\) and our angle is \(22^o\). \(Cos~(22)~=~\dfrac{x}{840}\) Once you get that, you can then subtract the higher balloon's distance vertically from the person from the lower balloon's distance from the person.

Extrinix:

And for reference if drawings make more sense to you:

1 attachment
xcoledd1:

@extrinix wrote:
You must use the \(SOH~CAH~TOA\) rule in order to solve this. For the lower balloon, your side value is on the Hypotenuse compared to the angle. Meaning you must use \(cos\) in order to figure out what the length of the \(adjacent\) side is. The adjacent side is the side that you're using to figure out the difference between the height of the balloons. \(Cos~(\theta)~=~\dfrac{Adjacent}{Hypotenuse}\) Now, your adjacent is undefined, and your hypotenuse is defined (515m). \(Cos~(15)~=~\dfrac{x}{515}\) If you put that into your calculator, you will have the \(adjacent\) side for the lower balloon.
what is the SOH CAH TOA

Extrinix:

@xcoledd1 wrote:
what is the SOH CAH TOA
\(sin = \dfrac{Opposite}{Hypotenuse}\) \(cos = \dfrac{Adjacent}{Hypotenuse}\) \(tan = \dfrac{Opposite}{Adjacent}\)

xcoledd1:

@extrinix wrote:
@xcoledd1 wrote:
what is the SOH CAH TOA
\(sin = \dfrac{Opposite}{Hypotenuse}\) \(cos = \dfrac{Adjacent}{Hypotenuse}\) \(tan = \dfrac{Opposite}{Adjacent}\)
thank you yea me and @coyote has the same math class and we are doing trigonemtry and I need help with understanding the stuff I dont understand it at all

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!