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Mathematics 20 Online
hellokitty265:

o.o

hellokitty265:

i need help on finding the area and perimeter

Nightmoon:

The way you would find the area ~ side*side = side^2 believe - If I can remember math right. Perimeter ~ Adding the sides together -

Nightmoon:

@nightmoon wrote:
The way you would find the area ~ side*side = side^2 believe - If I can remember math right. Perimeter ~ Adding the sides together -
So with this - you'd need to take the steps and use them cause - its something more of what you'd need to figure out so you're not just given the answer.

Aratox:

Well, if you divide the main shape into 2 smaller rectangles, you can complete the following steps: 1. Divide the larger shape into two smaller shapes. The dimensions of the two new rectangles are 11 in x 13 in (designated as Rect 1 in this example) and 26 in x 10 in (Rect 2). 2. Multiply to find the area by using the equation \[l \times w = A\] So for this example, (Rect 1) = 11 x 13 = 143 in while (Rect 2) = 26 x 10 = 260 in 3. Add the two sums together, to get a total of 403 in (this is your area). 4. To find the perimeter, use the equation \[P = 2(l+w)\] in which case you multiply the length and width 2 times. In this example, you would be using the length and width of both of the Rects (1 & 2): (Rect 1) = 2(11 + 13) = 35 in² (Rect 2) = 2(26 + 10) = 62 in² 5. Add the perimeter of both Rect 1 and 2 together, giving you 35 + 62 = 97 in². Hope this helps! Contact me via DMs for more help :)

Nightmoon:

Or there is that.. and that is a lot smarter of an explanation so USE THAT :D

jhonyy9:

@aratox wrote:
Well, if you divide the main shape into 2 smaller rectangles, you can complete the following steps: 1. Divide the larger shape into two smaller shapes. The dimensions of the two new rectangles are 11 in x 13 in (designated as Rect 1 in this example) and 26 in x 10 in (Rect 2). 2. Multiply to find the area by using the equation \[l \times w = A\] So for this example, (Rect 1) = 11 x 13 = 143 in while (Rect 2) = 26 x 10 = 260 in 3. Add the two sums together, to get a total of 403 in (this is your area). 4. To find the perimeter, use the equation \[P = 2(l+w)\] in which case you multiply the length and width 2 times. In this example, you would be using the length and width of both of the Rects (1 & 2): (Rect 1) = 2(11 + 13) = 35 in² (Rect 2) = 2(26 + 10) = 62 in² 5. Add the perimeter of both Rect 1 and 2 together, giving you 35 + 62 = 97 in². Hope this helps! Contact me via DMs for more help :)
ATTENTION please !!! perimeter measure unit is the (in) not squared for AREA use measure unit squared so (in^2)

Aratox:

@jhonyy9 wrote:
@aratox wrote:
Well, if you divide the main shape into 2 smaller rectangles, you can complete the following steps: 1. Divide the larger shape into two smaller shapes. The dimensions of the two new rectangles are 11 in x 13 in (designated as Rect 1 in this example) and 26 in x 10 in (Rect 2). 2. Multiply to find the area by using the equation \[l \times w = A\] So for this example, (Rect 1) = 11 x 13 = 143 in while (Rect 2) = 26 x 10 = 260 in 3. Add the two sums together, to get a total of 403 in (this is your area). 4. To find the perimeter, use the equation \[P = 2(l+w)\] in which case you multiply the length and width 2 times. In this example, you would be using the length and width of both of the Rects (1 & 2): (Rect 1) = 2(11 + 13) = 35 in² (Rect 2) = 2(26 + 10) = 62 in² 5. Add the perimeter of both Rect 1 and 2 together, giving you 35 + 62 = 97 in². Hope this helps! Contact me via DMs for more help :)
ATTENTION please !!! perimeter measure unit is the (in) not squared for AREA use measure unit squared so (in^2)
Thank you for the correction, and sorry, @hellokitty265!

jhonyy9:

@aratox wrote:
@jhonyy9 wrote:
@aratox wrote:
Well, if you divide the main shape into 2 smaller rectangles, you can complete the following steps: 1. Divide the larger shape into two smaller shapes. The dimensions of the two new rectangles are 11 in x 13 in (designated as Rect 1 in this example) and 26 in x 10 in (Rect 2). 2. Multiply to find the area by using the equation \[l \times w = A\] So for this example, (Rect 1) = 11 x 13 = 143 in while (Rect 2) = 26 x 10 = 260 in 3. Add the two sums together, to get a total of 403 in (this is your area). 4. To find the perimeter, use the equation \[P = 2(l+w)\] in which case you multiply the length and width 2 times. In this example, you would be using the length and width of both of the Rects (1 & 2): (Rect 1) = 2(11 + 13) = 35 in² (Rect 2) = 2(26 + 10) = 62 in² 5. Add the perimeter of both Rect 1 and 2 together, giving you 35 + 62 = 97 in². Hope this helps! Contact me via DMs for more help :)
ATTENTION please !!! perimeter measure unit is the (in) not squared for AREA use measure unit squared so (in^2)
Thank you for the correction, and sorry, @hellokitty265!
MORE ATTENTION please !!! thank you in advance

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