Question

Okay. here is another one. I will post the attachment in the comments. This is the last one. Thanks for the help guys.

Answer 1

@toga toga is rlly good in this

Answer 2

@hero

Answer 3

There's actually a few ways to go about this problem. Identifying the triangle, you can see it is an Isosceles Triangle, so you know which formulas to refer to.

Since you are given all three sides, you could use this formula: \( \Large A= \frac{1}{2} ( \frac{ \sqrt{a^2-b^2}}{4} * b) \)

Where "a" is the two equal sides, aka 15 in
and "b" is the base of the triangle, or "x=17 cm."

Answer 4

Actually no, disregard the above, since it is an Isosceles triangle, you can cut right down the middle of the triangle to make a right triangle.



Now you can use \(\large a^2+b^2=c^2 \) to find the height, \( h\).

\\[\large 8.5^2 +b^2 = 15^2 \]
\\[\large b^2=15^2-8.5^2 \]
\\[\large b \approx 12.3592 \]

Now you can use the area formula: \(\large A= \frac{1}{2}*b*h \)
\\[\large A = \frac{1}{2} (8.5)(12.3592)\]
Since this is only for half a triangle, you can multiply it by 2 to get the area for the full triangle, leaving you with just:
\\[\large A=8.5*12.3592 \approx 105.053~in \]

Answer 5

Though one thing that's throwing me off, why are the units in cm AND inches? Did you need to convert the measurements? Or is it just a mistake?

Answer 6

Damn