help
pls help
@toga
@alexis1415
@hero
One angle you can find is "b" It lies on a straight line with the given angles 51 and 110. As a rule, it is known that a straight line produces an angle of 180, so to find b: \(\large 51+b+110 = 180\) \(\large b+161=180 \) \(\large b= 19\)
Now with "a" we could use something known as the Vertical Angles Theorem. In this case, "a" would be equal to the angle 60; as vertically opposite angles are congruent. So you get \(\large a=60\)
So now you have \( b=19\) and \( a=60\) which you can use to find c. A triangle has interior angles that sum up to 180 degrees, so you could solve for c as so: \(\large 60+19+c=180 \) \(\large 79+c=180 \) \(\large c= 101 \)
And now that you have c, you can find angle d. Since \(\large c+d=180\) since they form a straight line: \(\large 101 + d= 180 \) \(\large d= 79 \)
Finally, you have angle d, and the angle of 51. All this information can be used to find "e" \(\large 51+79+e =180 \) I'm sure you can solve it from here
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