(algebra 1) need help with a few questions
(algebra 1) n
The equation you're looking for is y-y1=m(x-x1). So you're slow is outside the parentheses, your x is inside, and your y is one the left side of the equal sign
@toga
To find the equation in point-slope form that passes through the point (4, -2) with a slope of \( \frac{1}{2} \), we use the point-slope formula: \[ y - y_1 = m(x - x_1) \] Where \( (x_1, y_1) \) is the point (4, -2) and \( m \) is the slope \( \frac{1}{2} \). Plugging in the values: \[ y - (-2) = \frac{1}{2}(x - 4) \] This simplifies to: \[ y + 2 = \frac{1}{2}(x - 4) \] Thus, the equation in point-slope form is: C. \( y + 2 = \frac{1}{2}(x - 4) \) So, the correct answer is C.
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