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Mathematics 7 Online
bismil:

trig assignment

bismil:

1 attachment
bismil:

can someone help

Luigi0210:

The first thing you would need to do is find the length of 'AC', which you can do by using \(a^2+b^2=c^2\) You are given b = 2 and c = 5 \(\large a^2 +(2)^2 = (5)^2 \) Just calculate and get 'a' \(\large a^2 +4 = 25 \) \(\large a^2 = 21 \) \(\large a = \sqrt{21} \) Now that you have a, you can find the tan(B). Do you know which side(s) correspond to tangent?

Luigi0210:

Tangent would be \(\large tan(\theta) = \frac{opposite}{adjacent} \) So in this case, \(\large tan(B) = \frac{\sqrt{21}}{2} \)

ykbatman:

huh

ykbatman:

idek how to comprehend that

bismil:

@luigi0210 wrote:
Tangent would be \(\large tan(\theta) = \frac{opposite}{adjacent} \) So in this case, \(\large tan(B) = \frac{\sqrt{21}}{2} \)
ohhhh i get it finally

bismil:

thank you so much!!! im going to write this down

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