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trig assignment
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can someone help
The first thing you would need to do is find the length of 'AC', which you can do by using \(a^2+b^2=c^2\) You are given b = 2 and c = 5 \(\large a^2 +(2)^2 = (5)^2 \) Just calculate and get 'a' \(\large a^2 +4 = 25 \) \(\large a^2 = 21 \) \(\large a = \sqrt{21} \) Now that you have a, you can find the tan(B). Do you know which side(s) correspond to tangent?
Tangent would be \(\large tan(\theta) = \frac{opposite}{adjacent} \) So in this case, \(\large tan(B) = \frac{\sqrt{21}}{2} \)
huh
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idek how to comprehend that
@luigi0210 wrote:
Tangent would be \(\large tan(\theta) = \frac{opposite}{adjacent} \)
So in this case, \(\large tan(B) = \frac{\sqrt{21}}{2} \)
thank you so much!!! im going to write this down
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