Question

(algebra 1) help

Answer 1

So you are given the equation: \( 3x-6y=2 \)

First thing you need to do is get into slope-intercept form, y=mx+b

Subtract 3x
\(\large -6y=2-3x \)

Divide by -6:
\(\large y=\frac{2}{-6} -\frac{3x}{-6} \)

Simplify :

\(\Large y= \frac{1}{2} x -\frac{1}{3} \)

So now you have the slope of \(\large \frac{1}{2} \)

Answer 2

Since you want a line that is *perpendicular* rather than parallel, you have to use the negative reciprocal of the slope; so instead of 1/2 you would use '-2' with the ordered pair (-2, -5)

Now use the point-slope formula and simplify:
\(\large y- y_1 = m(x-x_1) \) where 'm' is slope, \(y_1\) is the y coordinate, and \(x_1\) is the x coordinate

\(\large y-(-5) = -2(x-(-2))\)

\(\large y+5 = -2(x+2) \)

\(\large y+5 = -2x-4 \)

\(\large y=-2x-9 \)

Hopefully you were able to understand what I did.