Question

GUYS I NEED HELPPPPPPPPPP

Answer 1

3x^6y^9 I think

Answer 2

\[\frac{ 9x^5y^8 }{ 3xy}=3x^5y^8x^{-1}y^{-1}=3x^{5-1}y^{8-1}=3x^4y^7\]

Answer 3

I swear I think thats 3x^4 y^7

Answer 4

I do not know

Answer 5

I haven't done this in a while

Answer 6

it is very simple and it is corrct.

Answer 7

You can subtract the exponents in the numerator by those in the denominator, as long as they belong to the same variable. Basically:

\[\frac{x^{a}}{x^{b}} = x^{a-b}\]

So we can look at each part, the first is 9/3, which just comes out to three. Now your equation should look like this:

\[\frac{3x^{5}y^{8}}{xy}\]

Using the property I mentioned, we should be able to subtract the exponents for both the x and the y...

\[3x^{5-1}y^{8-1}\]

Now simplify to get your final equation, and remember that if a variable has no exponent (meaning just an x or y) then there is actually a 1 there that should be used in problems like these. Have a great day!

Answer 8

w