Question

Let the function f be defined by y = f(x), where x and f(x) are real numbers.
f(x)=8 over x-4
f(2)
f(-3)
f(k)
f(k^2-1)=

Answer 1

its really just a matter of plugging in those f numbers in place of the x

Answer 2

\[f(2)=\frac{8}{2-4}\]
\[f(-3)=\frac{8}{-3-4}\]
\[f(k)=\frac{8}{k-4}\]
\[f(k^2 -1)=\frac{8}{k^2 -1-4}\]

Answer 3

sweet.. that is what i came up with on this one.. and i beleive if i simplify the f(2)= 8 over2-4 it comes out to -4... is that correct?

Answer 4

yes, thats right