Question

z/1 -1/z =0
is the answer
(z,-z)

Answer 1

\[\frac{z}{1}-\frac{1}{z}=0\]
denominator is (1*z)
\[z*z= z^{2}\]
\[(z^{2}-1)=o\]
factor:
(x+1)(x-1) =0
z = 1
z = -1
If I deserve medal then give me one.

Answer 2

how do I do that, I am new to this

Answer 3

next to my name click give medal

Answer 4

di u se/

Answer 5

thank

Answer 6

I think I did it

Answer 7

your welcome

Answer 8

yes, any more question?

Answer 9

yes I do

Answer 10

post it I will try the best

Answer 11

ok

Answer 12

find the LCM
y^3 +4y^2 + 4y, y^2-4y

Answer 13

2 question?

Answer 14

no, thats 1

Answer 15

should i post it on the otherside so u can get credit for this as well

Answer 16

\[y^{3}+4y ^{2}+4y \]
and another on is :
\[y^{2}-4y\]

Answer 17

?

Answer 18

look like u have 2 not 1 ?

Answer 19

the question gives 5 numbers and ask me to find the LCM
the way it wants me to answer is
number (number)^exponent (y-number)

Answer 20

LCM = 4y

Answer 21

y^3 +4y^2 + 4y= 4y(y^2 +y+1)
y^2-4y = 4y(y-1)
than LCM is ; 4y

Answer 22

wailt

Answer 23

I'm not sure u may re post question to see some one beter

Answer 24

I can factor nut not sure LCM

Answer 25

no prroblem thanks for trying, I do have something that you may be able to help with

Answer 26

y^3 +4y^2 + 4y = y(y^2+4y+4)
= y(y+2)(y+2)
=y (y+2)^2
y=0 , y=-2

Answer 27

y^2-4y = y(y-4)
y = 0 , y =4

Answer 28

here goes another one
x^2-3x+2/x^2+5x-6

Answer 29

it states that i should simplremoving factors of one

Answer 30

I can do this ,give a time I'm slow

Answer 31

ok, lol no problem, and thank u

Answer 32

\[(x^{2}-3x+2)\div(x ^{2}+5x -6)\]
I want made suse I'm right?

Answer 33

no not division its factoring

Answer 34

\[\frac{(x-2)(x-1)}{(x+3)(x-2)}\]

Answer 35

no?

Answer 36

x- 2 cancel\[\frac{(x-1)}{(x+3}\]

Answer 37

that right?

Answer 38

i believe so, im horrible at math

Answer 39

I sure it correct

Answer 40

ok, thanx

Answer 41

u r welcom