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Integrate: (-3x^2)/(x^3 +2)^2 without using log
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substitute u = x^3
du = 3x^2 dx
substitude u=x^3+2 that will be more helpful
sorry substitute u = x^3+2
yes, thats what I meant i didnt type in the +2
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\[\int\limits (-3x^2)dx/(x^3+2)^2=\int\limits -du/u^2=1/u+c=1/(x^3+2)+c\]
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