Question

MATH HELP!!

Answer 1

^^^^^^^^^^^^^^^^^^^^^^^^

Answer 2

\[\sqrt{4x+5}-\sqrt{x-1}=\sqrt{x+4}\]

Answer 3

square both sides, get
\[4x+5+x-1-2\sqrt{4x+5}\sqrt{x-1}=x+4\]
or
\[4x=2\sqrt{4x+5}\sqrt{x-1}\] or
\[2x=\sqrt{4x+5}\sqrt{x-1}\] and then square again

Answer 4

okay thanks

Answer 5

i think that works
second time you get \(4x^2=(4x+5)(x-1)=4x^2+x-5\)
or \(0=x-5\) so \(x=5\)

Answer 6

yes it did...thanks for helping me work it out