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Find S12 for 1 + 6 + 11 + 16 +…
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looks like an arithmetic series..
what have you tried?
i dont even know how to do it i dont understand it
\[S_n = \frac{n}{2}[2a+(n-1)d]\] this is the formula you use
oh wow lol can you break that down please
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well have you by chance looked at your textbook or something?
the first term is \(a = 1\) and the \(d\) common difference is \(5\)
i dont have a text book i do it online
then you're finding \(S_{12}\)
so what am i doing exactly am i adding or subtracting
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\[s_{12} = \frac{12}{2} \left[2(1)+(12-1)*5\right] = ...\] since n = 12, a = 1 , d = 5; i just subbed it in
would it be 342
well if you got \(342\) then i assume that you're right
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