Math 4

Vectors/Vectors Applications

Question

Math 4

Vectors/Vectors Applications

Joe348 · Answer

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surjithayer · Answer

|dw:1675743900135:dw|
horizontal component of force=110 cos 50+70 cos 130
=110 cos50+70 cos(180-130)
=110 cos 50-70cos 50
=40 cos 50
$$\approx ~25.71~pounds$$
vertical component of force=110 cos 40+70 cos 40
=180cos40
$$\approx137.89 ~pounds$$
resultant force=
$$=\sqrt{25.71^2+137.89^2}$$
$$\approx140.27~pounds$$

BestQcGuitarPlayer · Answer

nah im stupid

Joe348 · Answer

@surjithayer wrote:

Created with Raphaël4040505011070Reply Using Drawing horizontal component of force=110 cos 50+70 cos 130 =110 cos50+70 cos(180-130) =110 cos 50-70cos 50 =40 cos 50 $$\approx ~25.71~pounds$$ vertical component of force=110 cos 40+70 cos 40 =180cos40 $$\approx137.89 ~pounds$$ resultant force= $$=\sqrt{25.71^2+137.89^2}$$ $$\approx140.27~pounds$$

Thank you so much bro!

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