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Joe348:
Math 4 Vectors/Vectors Applications
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Joe348:
surjithayer:
|dw:1675743900135:dw| horizontal component of force=110 cos 50+70 cos 130 =110 cos50+70 cos(180-130) =110 cos 50-70cos 50 =40 cos 50 \[\approx ~25.71~pounds\] vertical component of force=110 cos 40+70 cos 40 =180cos40 \[\approx137.89 ~pounds\] resultant force= \[=\sqrt{25.71^2+137.89^2}\] \[\approx140.27~pounds\]
BestQcGuitarPlayer:
nah im stupid
Joe348:
Thank you so much bro!
@surjithayer wrote:
Created with Raphaƫl4040505011070Reply Using Drawing
horizontal component of force=110 cos 50+70 cos 130
=110 cos50+70 cos(180-130)
=110 cos 50-70cos 50
=40 cos 50
\[\approx ~25.71~pounds\]
vertical component of force=110 cos 40+70 cos 40
=180cos40
\[\approx137.89 ~pounds\]
resultant force=
\[=\sqrt{25.71^2+137.89^2}\]
\[\approx140.27~pounds\]
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