Ask your own question, for FREE!
Mathematics 58 Online
Joe348:

Math 4 Vectors/Vectors Applications

Joe348:

1 attachment
surjithayer:

|dw:1675743900135:dw| horizontal component of force=110 cos 50+70 cos 130 =110 cos50+70 cos(180-130) =110 cos 50-70cos 50 =40 cos 50 \[\approx ~25.71~pounds\] vertical component of force=110 cos 40+70 cos 40 =180cos40 \[\approx137.89 ~pounds\] resultant force= \[=\sqrt{25.71^2+137.89^2}\] \[\approx140.27~pounds\]

BestQcGuitarPlayer:

nah im stupid

Joe348:

@surjithayer wrote:
Created with Raphaƫl4040505011070Reply Using Drawing horizontal component of force=110 cos 50+70 cos 130 =110 cos50+70 cos(180-130) =110 cos 50-70cos 50 =40 cos 50 \[\approx ~25.71~pounds\] vertical component of force=110 cos 40+70 cos 40 =180cos40 \[\approx137.89 ~pounds\] resultant force= \[=\sqrt{25.71^2+137.89^2}\] \[\approx140.27~pounds\]
Thank you so much bro!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!