Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.
Do you know how to find the slope of the line containing both of those points?
i think y1-y2/x1-x2
That's it, so what is the slope you get from that?
6
Let's look at the y's first: y2 = 3 and y1 = 2 y2-y1= 1 Now the x's x2 = 6 x1 = 2 x2-x1= 4 So our slope will be: m = 1/4
From here we use the point slope formula. We can use either point they'll give you the same equation at the end. The point slope formula is: y−y1=m(x−x1)
So: m = 1/4 x1 = 6 y1 = 2 Putting that into our formula: y - 2 = 1/4 (x - 6) Now we solve for y: y - 2 = 1/4 x - 6/4 y = 1/4 x + 2 - 6/4 y = 1/4 x + 2/4 y = 1/4 x + 1/2
4x + 4y = 6 x + 4y = 12 4x + 4y = –12 x – 4y = –6 these are the answers i got the first wrong and i do not knw where i went wrong
Join our real-time social learning platform and learn together with your friends!